
Lewis structures, devised by Gilbert N. Lewis, visually represent electron arrangements in molecules. By depicting valence electrons as dots and bonds as lines, Lewis structures predict a molecule's shape and properties based on the octet rule. This rule states that atoms tend to achieve stability by having eight electrons in their outer shell. Lewis structures adhere to this rule, offering a clear picture of chemical bonding.
Nitrogen tribromide (NBr3) is a compound consisting of one nitrogen atom bonded to three bromine atoms. It is a colorless liquid that decomposes readily and is highly reactive. Due to its instability, it is typically handled under controlled conditions and is used primarily in research and laboratory settings.
Let's dive into drawing the Lewis structure of NBr3:
Step 1: Identify the Central Atom: Nitrogen (N) is the central atom in NBr3 because it's less electronegative than bromine.
Step 2: Calculate Total Valence Electrons: Nitrogen contributes 5 valence electrons, and each bromine contributes 7, giving a total of 5 + (3 x 7) = 26 valence electrons.
Step 3: Arrange Electrons Around Atoms: Connect each bromine atom to the central nitrogen atom with a single bond (line) and distribute remaining electrons as lone pairs around each bromine atom.
Step 4: Fulfill the Octet Rule: Ensure each bromine atom has 8 electrons (2 lone pairs and 1 bonding pair), and the nitrogen atom has 8 electrons (2 lone pairs and 3 bonding pairs).
Step 5: Check for Formal Charges: Formal charges may not be necessary as all atoms have achieved the octet rule.
The structure of nitrogen tribromide consists of a central nitrogen atom surrounded by eight electrons or four electron pairs, with no lone pair of electrons, so that the molecular geometry of NBr3 is trigonal cone geometry. There is a 110.4 degree Angle between the Br-N-Br bonds.

This theory addresses electron repulsion and the need for compounds to adopt stable forms. In NBr3, three sigma bonds form between nitrogen and bromine, with three lone pairs on each bromine atom. Although nitrogen has only five valence orbitals, the Lewis structure suggests three bond pairs, implying the use of p-orbitals in this compound. Advanced calculations reveal the electronic structure consists of three delocalized bonds across all four atoms, rather than distinct bonds involving d-orbitals.
The Lewis structure indicates that NBr3 adopts a triangular cone geometry. In this arrangement, three brominated atoms are symmetrically distributed around the central nitrogen atom, forming three bond pairs. This geometry minimizes electron-electron repulsion, resulting in a stable configuration.
The orbitals involved and the bonds produced during the interaction of Nitrogen and bromine molecules will be examined to determine the hybridization of Nitrogen tribromide. 2s, 2px, 2py, and 2pz are the orbitals involved. The Nitrogen atom, which is the central atom in its ground state, will have the 2s22p3 configuration in its formation.
The electron pairs in the 2s and 2px orbitals become unpaired in the excited state, and one of each pair is promoted to the unoccupied 2py and 2pz orbitals. All four half-filled orbitals (one 2s, two 2p) hybridize now, resulting in the production of four sp3 hybrid orbitals.
The bond angle in NBr3 is approximately 110.4 degrees. This angle arises from the trigonal pyramidal geometry of the molecule, where the three bromine atoms are positioned around the central nitrogen atom, with one lone pair of electrons on nitrogen, leading to the 110.4-degree bond angles between adjacent bromine atoms. The bond length in NBr3 is approximately 0.185 nm, reflecting the strength of the N-Br bonds and the overall arrangement of atoms in the molecule. This configuration contributes to the stability and reactivity of nitrogen tribromide.
| Nitrogen Tribromide (CAS 15162-90-0) | |
| Molecular formula | NBr3 |
| Molecular shape | trigonal pyramidal geometry |
| Polarity | polar |
| Hybridization | sp3 hybridization |
| Bond Angle | 110.4 degrees |
| Bond length | 0.185 nm |
Nitrogen tribromide (NBr3) is a polar molecule characterized by three polar nitrogen-bromine bonds, which arise from the differing electronegativities of the involved atoms. This polarity results from the significant electronegativity difference between nitrogen (3.0) and bromine (2.8). The difference of 0.2 between these values contributes to the molecule's overall polar nature. Additionally, the trigonal pyramidal geometry, caused by the presence of a lone pair on the nitrogen atom, leads to an uneven distribution of electron density, enhancing the polarity of the molecule.
To calculate the total bond energy of NBr3, first, look up the bond energy for a single nitrogen-bromine (N-Br) bond, which is approximately 220 kJ/mol. NBr3 has three N-Br bonds, so you multiply the bond energy of one N-Br bond by the number of bonds. This gives a total bond energy of 660 kJ/mol for NBr3. This value represents the energy required to break all the N-Br bonds in one mole of NBr3 molecules.
Bond order is the number of chemical bonds between a pair of atoms. In the Lewis structure of NBr3, each nitrogen-bromine bond is a single bond, so the bond order for each N-Br bond is 1. If a molecule has resonance structures, bond order is averaged over the different structures, but NBr3 does not have resonance, so the bond order remains 1.
Electron groups in a Lewis structure include both bonding pairs (shared electrons) and lone pairs (non-bonded electrons) around an atom. In NBr3, each nitrogen atom has three electron groups around it, corresponding to the three N-Br bonds (three bonding pairs and no lone pairs on nitrogen).
In a Lewis dot structure, the dots represent valence electrons. Each dot corresponds to one valence electron of an atom. In NBr3, nitrogen is surrounded by three bonding pairs (represented by lines in the Lewis structure) and each bromine atom is represented by three pairs of dots (lone pairs) and one bonding pair with nitrogen. The dots help visualize how electrons are shared or paired between atoms.
![]() |
![]() |
![]() |