
Lewis structures, devised by Gilbert N. Lewis, visually represent electron arrangements in molecules. By depicting valence electrons as dots and bonds as lines, Lewis structures predict a molecule's shape and properties based on the octet rule. This rule states that atoms tend to achieve stability by having eight electrons in their outer shell. Lewis structures adhere to this rule, offering a clear picture of chemical bonding.
Bismuth Triiodide (BiI3) is a compound composed of one bismuth atom bonded to three iodine atoms. It is a solid at room temperature and exhibits unique properties due to its molecular structure. BiI3 is commonly used in various scientific research applications and has specific industrial uses.
Let's dive into drawing the Lewis structure of BiI3:
Step 1: Identify the Central Atom: Bismuth (Bi) is the central atom in BiI3 because it's less electronegative than iodine.

Step 2: Calculate Total Valence Electrons: Bismuth contributes 5 valence electrons, and each iodine contributes 7, giving a total of 5 + (3 x 7) = 26 valence electrons.
Step 3: Arrange Electrons Around Atoms: Connect each iodine atom to the central bismuth atom with a single bond (line) and distribute remaining electrons as lone pairs around each iodine atom.
Step 4: Fulfill the Octet Rule: Ensure each iodine atom has 8 electrons (2 lone pairs and 1 bonding pair), and the bismuth atom has 8 electrons (2 lone pairs and 3 bonding pairs).
Step 5: Check for Formal Charges: Formal charges may not be necessary as all atoms have achieved the octet rule.
The structure of bismuth triiodide consists of a central bismuth atom single-bonded to three iodine atoms. This arrangement suggests a trigonal pyramidal geometry around the bismuth atom, highlighting its bonding characteristics. The bond angle between the iodine atoms is approximately 109.5 degrees.

Molecular orbital theory addresses the bonding in bismuth triiodide. In BiI3, three sigma bonds form between bismuth and iodine atoms, while there is one lone pair on the bismuth. The Lewis structure indicates three bond pairs and one lone pair, resulting in a stable molecular configuration that minimizes electron repulsion.
The hybridization of the bismuth atom in BiI3 involves the orbitals participating in bonding. Bismuth has the electron configuration of 6s²6p³. In the formation of BiI3, the 6s and 6p orbitals hybridize to create four sp³ hybrid orbitals. Three of these hybrid orbitals form bonds with the iodine atoms, while the fourth holds the lone pair, contributing to the trigonal pyramidal geometry.
In bismuth triiodide, the bond angle between the I-Bi-I bonds is approximately 109.5 degrees, consistent with its trigonal pyramidal geometry. The bond length for the Bi-I bond is approximately 0.287 nm (287 pm), reflecting the strength of the sigma bonds formed between bismuth and iodine. These bond angles and lengths contribute to the overall stability and geometry of the molecule.
| Bismuth Triiodide Cas 7787-64-6 | |
| Molecular formula | BiI3 |
| Molecular shape | Trigonal Pyramidal |
| Polarity | polar |
| Hybridization | sp3 hybridization |
| Bond Angle | 109.5 degrees |
| Bond length | 287 pm |
To determine if a Lewis structure is polar, examine the molecular geometry and bond polarity. In the case of bismuth triiodide (BiI3), the Lewis structure shows bismuth at the center bonded to three iodine atoms. BiI3 has a trigonal planar geometry, where the three iodine atoms are symmetrically arranged around the bismuth atom. Although the Bi-I bonds are polar, the symmetry of the molecule causes the dipole moments to cancel out, making BiI3 a nonpolar molecule.
To calculate the total bond energy of BiI3, first, look up the bond energy for a single bismuth-iodine (Bi-I) bond, which is approximately 210 kJ/mol. BiI3 has three Bi-I bonds, so you multiply the bond energy of one Bi-I bond by the number of bonds. This gives a total bond energy of 630 kJ/mol for BiI3. This value represents the energy required to break all the Bi-I bonds in one mole of BiI3 molecules.
Bond order is the number of chemical bonds between a pair of atoms. In the Lewis structure of BiI3, each bismuth-iodine bond is a single bond, so the bond order for each Bi-I bond is 1. If a molecule has resonance structures, bond order is averaged over the different structures, but BiI3 does not have resonance, so the bond order remains 1.
Electron groups in a Lewis structure include both bonding pairs (shared electrons) and lone pairs (non-bonded electrons) around an atom. In BiI3, each bismuth atom has three electron groups around it, corresponding to the three Bi-I bonds (three bonding pairs and no lone pairs on bismuth).
In a Lewis dot structure, the dots represent valence electrons. Each dot corresponds to one valence electron of an atom. In BiI3, bismuth is surrounded by three bonding pairs (represented by lines in the Lewis structure) and each iodine atom is represented by three pairs of dots (lone pairs) and one bonding pair with bismuth. The dots help visualize how electrons are shared or paired between atoms.
When determining the best Lewis structure for BiI3, it's important to consider both the bonding and the arrangement of electrons to ensure the most stable representation. Choosing the correct structure helps in understanding its molecular properties and behavior. If you're exploring how to choose the best Lewis structure for BiI3 or other compounds, Guidechem provides access to a wide range of global suppliers of BiI3. Here, you can find the ideal raw materials to support your research and applications.
![]() |
![]() |